Electrical Formulas

Essential DC, AC single-phase, three-phase, power factor, and impedance formulas.

16 reference items · 5 sections

DC Circuit Formulas

Ohm's Law

V = I × R
Ohm's Law
VariableDescriptionUnit
VVoltageVolts
ICurrentAmperes
RResistanceOhms (Ω)
Variations:Find Current: I = V ÷ RFind Resistance: R = V ÷ I
The fundamental relationship between voltage, current, and resistance in an electrical circuit.

DC Power

P = V × I
DC Power
VariableDescriptionUnit
PPowerWatts
VVoltageVolts
ICurrentAmperes
Variations:Using R: P = I² × RUsing R: P = V² ÷ RFind Current: I = P ÷ VFind Voltage: V = P ÷ I
Power consumed by a DC circuit.

Electrical Energy

E = P × t
Electrical Energy
VariableDescriptionUnit
EEnergyWatt-hours (Wh)
PPowerWatts
tTimeHours
Variations:In kWh: kWh = (W × h) ÷ 1000
1 kWh = 1,000 Wh. Utility billing is typically in kWh.

Series Resistance

R_total = R₁ + R₂ + R₃ + ...
Series Resistance
VariableDescriptionUnit
R_totalTotal resistanceOhms (Ω)
R₁,R₂Individual resistancesOhms (Ω)
In a series circuit, total resistance is the sum of all resistances. Current is the same through all components.

Parallel Resistance

1/R_t = 1/R₁ + 1/R₂ + 1/R₃ + ...
Parallel Resistance
VariableDescriptionUnit
R_tTotal resistanceOhms (Ω)
R₁,R₂Individual resistancesOhms (Ω)
Variations:Two Resistors: R_t = (R₁×R₂)÷(R₁+R₂)
For two resistors: R_t = (R₁ × R₂) ÷ (R₁ + R₂). Voltage is the same across all branches.

AC Single-Phase Formulas

Single-Phase Power

P = V × I × PF
Single-Phase Power
VariableDescriptionUnit
PReal powerWatts
VVoltageVolts
ICurrentAmperes
PFPower factordecimal 0-1
Variations:Find Amps: I = P ÷ (V × PF)Find Voltage: V = P ÷ (I × PF)
PF = 1.0 for purely resistive loads (heaters, incandescent). PF < 1.0 for motors, fluorescents.

Apparent Power (1Φ)

S = V × I
Apparent Power
VariableDescriptionUnit
SApparent powerVolt-Amperes (VA)
VVoltageVolts
ICurrentAmperes
Variations:kVA: kVA = (V × I) ÷ 1000Find Amps: I = kVA × 1000 ÷ V
Apparent power is the product of voltage and current without considering power factor. kVA = VA ÷ 1000.

Amps from HP (1Φ)

I = (HP × 746) ÷ (V × Eff × PF)
Single-Phase Amps from Horsepower
VariableDescriptionUnit
ICurrentAmperes
HPHorsepowerHP
VVoltageVolts
EffMotor efficiencydecimal
PFPower factordecimal
1 HP = 746 Watts. Typical motor efficiency: 0.80-0.95. Typical PF: 0.80-0.90.

AC Three-Phase Formulas

Three-Phase Power

P = √3 × V × I × PF
Three-Phase Power
VariableDescriptionUnit
PReal powerWatts
√3Square root of 3≈ 1.732
VLine voltageVolts
ILine currentAmperes
PFPower factordecimal
Variations:Find Amps: I = P ÷ (1.732 × V × PF)kW: kW = (1.732×V×I×PF)÷1000
Use line-to-line voltage (e.g., 208V, 240V, 480V). √3 ≈ 1.732.

Apparent Power (3Φ)

S = √3 × V × I
Three-Phase Apparent Power
VariableDescriptionUnit
SApparent powerVA
VLine voltageVolts
ILine currentAmperes
Variations:kVA: kVA = (1.732×V×I) ÷ 1000Find Amps: I = kVA×1000 ÷ (1.732×V)

Amps from HP (3Φ)

NEC 430.250
I = (HP × 746) ÷ (1.732 × V × Eff × PF)
Three-Phase Amps from Horsepower
VariableDescriptionUnit
ICurrentAmperes
HPHorsepowerHP
VLine voltageVolts
EffMotor efficiencydecimal
PFPower factordecimal
For motor circuit sizing, use NEC Table 430.250 FLC values instead of calculating from nameplate.

Power Factor & Power Triangle

Power Factor

PF = P ÷ S = cos(θ)
Power Factor
VariableDescriptionUnit
PFPower factordecimal 0-1
PReal power (true power)Watts
SApparent powerVA
θPhase angledegrees
Variations:As %: PF% = (P ÷ S) × 100

Power Triangle

P (Watts) = Real Power — does actual work S (VA) = Apparent Power — total circuit power Q (VAR) = Reactive Power — stored/returned by inductors/capacitors
Q = √(S² - P²)
Reactive Power
VariableDescriptionUnit
QReactive powerVAR
SApparent powerVA
PReal powerWatts
Variations:Find S: S = √(P² + Q²)
S² = P² + Q² (Pythagorean relationship)

Impedance, Reactance & Resonance

Impedance

Z = √(R² + X²)
Impedance
VariableDescriptionUnit
ZImpedanceOhms (Ω)
RResistanceOhms (Ω)
XNet reactance (X_L - X_C)Ohms (Ω)
Variations:AC Ohm's Law: I = V ÷ Z
Impedance is the total opposition to current flow in an AC circuit. Ohm's Law for AC: V = I × Z.

Inductive Reactance

X_L = 2π × f × L
Inductive Reactance
VariableDescriptionUnit
X_LInductive reactanceOhms (Ω)
fFrequencyHertz (Hz)
LInductanceHenrys (H)
Variations:Find L: L = X_L ÷ (2π × f)
At 60 Hz: X_L = 377 × L. Inductive reactance increases with frequency.

Capacitive Reactance

X_C = 1 ÷ (2π × f × C)
Capacitive Reactance
VariableDescriptionUnit
X_CCapacitive reactanceOhms (Ω)
fFrequencyHertz (Hz)
CCapacitanceFarads (F)
Variations:Find C: C = 1 ÷ (2π × f × X_C)
Capacitive reactance decreases with frequency — opposite of inductive reactance.

Resonant Frequency

f_r = 1 ÷ (2π × √(L × C))
Resonant Frequency
VariableDescriptionUnit
f_rResonant frequencyHertz (Hz)
LInductanceHenrys (H)
CCapacitanceFarads (F)
Variations:Find L: L = 1 ÷ (4π²f²C)Find C: C = 1 ÷ (4π²f²L)
At resonance, X_L = X_C, so impedance is purely resistive (Z = R). Current is maximum in a series RLC circuit and minimum in a parallel RLC circuit.

Take It With You

Access quick reference, 8,000+ practice questions, and NEC calculators anywhere with the NEC Mastery app.